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Let f(x)=log of 8 times (1−2x). Then f′(x):
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\[Let f(x)=\log_{8} (1−2x). Then f'(x)\]
\[\Large f(x) = \log_{8}(1-2x)\] \[\Large f^{\prime}(x) = \frac{d}{dx}\left(\log_{8}(1-2x)\right)\] \[\Large f^{\prime}(x) = \frac{1}{(1-2x)\ln(8)}\frac{d}{dx}\left(1-2x\right)\] \[\Large f^{\prime}(x) = \frac{-2}{(1-2x)\ln(8)}\]
Oh! I was multiplying it by positive 2. Makes sense. Thank you!
You're welcome, glad it makes sense.
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