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What is the inverse of this quadratic function? y=4-x^2+3x,,, thx
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just plug y in for x and x in for y; then solve for y
x=4-y^2+3y x=-y^2+3y+4 0=-y^2+3y-x+4 But now what?
solve for y now...|dw:1333326025169:dw| from that last line, can you solve for y? that will be your inverse. but also consider the domain for f^-1(x) now....
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