Question

Can any one help me?

Answer 1

with?

Answer 2

The length of a rectangle is 1yd more than twice its width, and the area of the rectangle is 66yd^2. find the dimensions of the rectangle.

Answer 3

66/(2x+1)=x
(2x^2)+x=66
(2x^2)+x-66=0
=(-6 + -1x)(11 + -2x)
Eliminate (-6 + -1x) because that leads to a negative length
11-2x=0
x=5.5
Dimension: 5.5yd X 12 yd

Answer 4

Thank you!

Answer 5

The length of a rectangle is 5yd more than twice its width, and the area of the rectangle is 88yd^2. Find the dimensions of the rectangle.
Length:___yd
Width:___yd