Question

what are the steps to factoring this: 8x^4+10x^2-3

Answer 1

you can use substitution
let u=x^2
then factor 8u^2+10u-3
=(2u+3)(4u-1)
u=x^2, substitute x^2 back in for u
=(2x^2+3)(4x^2-1)
you can factor further because the second binomial is a difference of 2 squares
=(2x^2+3)(2x-1)(2x+1)