Question

I totally forgot how to do this??? D:

Answer 1

Use a trig function.\[c=15\sin40^{o}\]

Answer 2

Thank yoou! Can you help me with this one too??

Answer 3

Use the cos function. Recall that sin = opposite/hypotenuse, cos = adjacent/hypotenuse. In this case\[\cos(48^o)=c/51\]