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Mathematics 20 Online
OpenStudy (anonymous):

Given: h(x)=x^2-5x+7. h(b+1)= ?

OpenStudy (lgbasallote):

replace all x by (b+1) ^_^

OpenStudy (anonymous):

(b+1)^2 - 5(b+1) + 7

OpenStudy (anonymous):

If you foil it and everything, you would get b^2-3b+9

OpenStudy (lgbasallote):

+9? the constants would be 1 - 5 + 7...so it's 3..might wanna recheck your solution @cococupcoffee ^_^

OpenStudy (anonymous):

Yes, my bad. sorry, it's 3 (forgot to distribute earlier). Thanks, Igbasallote.

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