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Solve for g. √6g-23=√12-g
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how will i solve g
Is your question like this? \[\sqrt{6} g -23 = \sqrt{12}-g\]
In this is your equation than no solutions exist from wolfam http://www.wolframalpha.com/input/?i=sqrt%286g%29+-+23+%3D+sqrt%2812-g%29
@samifarooqi What is your question exactly? 1. \[\sqrt{6} g -23 = \sqrt{12} -g\]2. \[\sqrt{6g -23} = \sqrt{12 -g}\] Or?
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liek that
Okay, \[\sqrt{6g-23} = \sqrt{12-g}\] square both sides \[\sqrt{6g-23}^2 = \sqrt{12-g}^2\] Then you'll get \[6g-23 = 12-g\] Do you know how to do it from here?
no....i have trouble in math
But do you understand the above workings?
o yes i got it thanks
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