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Explain how he might have used the Sn formula to get his result.
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i can prove that ... without using Sn
1 + 2 + 3 + ... + 100 100 + 99 + 98 + ... + 1 ______________________________ 101 + 101 + 101 ..... + 101 so you have 100*101. divide that by 2 to get your answer...
exactly as @dpaInc
because you have 100 of those 101...
let x = 1 + 2 + 3 + ... + 100 so 1 + 2 + 3 + ... + 100 = x 100 + 99 + 98 + ... 1 = x ___________________________ 101+ 101 +101...+101 = 2x 101*100 = 2x so x = 100*101/2 = 50*101
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