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Mathematics 12 Online
OpenStudy (anonymous):

How do I find x in this problem? Picture shown below.

OpenStudy (anonymous):

OpenStudy (amistre64):

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OpenStudy (amistre64):

looks to me like; a/2 + (180-b/2) + c = 180 would account for all the angles in one of those relevant triangles

OpenStudy (anonymous):

how did you get a b c? I just have x

OpenStudy (amistre64):

20/2 + 180-(x+60)/2 + x = 180 they are just generic variables to help me sort thru it; i found them on the keyboard.

OpenStudy (anonymous):

funny. so is that how I solve it now? just 20/2=10+180 how do I divide with x and 60?

OpenStudy (anonymous):

or can we just multiply 180 by 2?

OpenStudy (amistre64):

there is a "thrm" that deals with this that i can never remember so I tend to have to build it anew by simpler ideas every time i do it :)

OpenStudy (amistre64):

10 - x/2 + 30 + x = 0 40 = x/2 - x 40 = x(1/2 - 1) 40 = x(-1/2) -80 = x ; im gonna assume i made a sign error someplace so I have to rechk it

OpenStudy (amistre64):

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