Question

Find the area of a regular pentagon with a side of 6 ft. Give the answer to the nearest tenth.

Answer 1

i believe it would be the area created by 5 isotriangles that have a base of 6

Answer 2

the length of a side would be s= 6sin(56)/sin(72)

\[5*\frac{18sin(56)}{sin(72)}\to\ \frac{90sin(56)}{sin(72)}\]
IF i see it right

Answer 3

my 56 is bad :)

Answer 4

180-70-2

110-2 = 108

108/2 = 54

change 56 to 54