Question

Need help! Discriminant of 3x^2-2x+9=0?

Answer 1

Discriminant... So 0, correct?

Answer 2

\[b^2-4ac\]
\[a=3,b=-2,c=9\] compute

Answer 3

b^-4ac
(-2)^2-4x3x9

Answer 4

We have
\[3x^2-2x+9=0\]
Standard quadratic equation
\[ax^2+bx+c=0
\]
\[Discriminant(D)=b^2-4ac\]
Here b=-2
a=3
c=9
so
\[D=(-2)^2-4 \times 3 \times 9=4-4 \times 3 \times 9=-104\]

Answer 5

(104)^.5i (imaginary).

Answer 6

Whoa, thanks guys. You're awesome