Question

Solve, but please show work: x^2/12 - 2x/3 - 4=0

Answer 1

\[\Large \frac{x^2}{12}-\frac{2x}{3}-4=0 \] do you mean this? :)

Answer 2

\[\frac{1}{12}x^2-\frac{2}{3}x-4=0\]

Answer 3

It just says math processing error

Answer 4

That's quadratic equation... you have \[\Large a=\frac{1}{12} \quad b=-\frac23 \quad c=-4\]

use this formula...

\[\Large x_{1/2}=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\]

just substitute and grab calculator (if you need it ! :P) LOL ;)

Answer 5

Okay thanks(:

Answer 6

@dylan82 are you still having a problem viewing the math stuff?

Answer 7

x^2/12 - 2x/3 - 4=0
Multiply each member of the equation by 12 to clear fractions.
x^12 - 8x - 48 = 0
This factors to:
(x - 12 ( x + 4) = 0
By the Zero Product Property
x - 12 = 0 or x + 4 = 0
x = 12 or x = -4

Answer 8

@myininaya Not any more