Question

Solve.

5
7
11
35

Answer 1

\[\Large \sqrt{6g-23}=\sqrt{12-g}\]
square both sides and you get...

\[\Large 6g-23=12-g\]

now move terms...
\[\Large 6g+g=12+23\]

\[\Large 7g=35 \longrightarrow g=\frac{35}{7}\]

and finally \[\LARGE g=5\]