Question

Solve each radical equation by using algebra. Check your solution. I will use sq. rt for square root.

1. sq. rt of (x- 5) = 3

2. sq. rt of ( 2x - 1) = x

3. 3 sq. rt of( x - 2) = 2 sq. rt of( x)

4. sq. rt. of (3x - 2) = x - 2

Answer 1

PLEASE HELP THIS IS DUE IN 4 HOURS

Answer 2

1. \[\Large \sqrt{2x-1}=x\] is the first one like this??

Answer 3

second one..

Answer 4

Thats exactly how its written, exactly how i typed it

Answer 5

but you said you'll use sq.rt for square root, then why did you type sq.rt before equation ? :S ... ? could you draw them please (equations)

Answer 6

1. \[(\sqrt{x-5})^{2}=(3)^2\]
x-5=9
x=14

Answer 7

2. \[(\sqrt{2x-1})^{2}=(x)^{2}\]
2x-1=x^2
-x^2+2x-1 --> (solve it with Quadratic quation to find x)

Answer 8

3. \[(3\sqrt{x-2})^{2}=(2\sqrt{x})^{2}\]
9(x-2)=4(x)
9x-18=4x
9x-4x=18
5x=18
x=3.6

Answer 9

4. \[(\sqrt{3x-2})^{2}=(x-2)^{2}\]
\[3x-2=x ^{2}-4x+4\]
7x-6=x^2
-x^2+7x-6 -> (solve with quadratic equation)