Question

Solve the logarithmic equation.
log(x+3)=1-log x

Answer 1

isolate all the ones with x first..

Answer 2

thts wht you'll get:
logx+log3=1-logx
2logx=1-log3

Answer 3

logx + log3 = log(3x) according to Product Law. Might wanna recheck that @math456 ^_^

Answer 4

log 10=1 so
log(x+3)=log 10-log x
log(x+3)+log x=log10
log(x^2+3x)=log10
get the antilog of both sides to end up with
x^2+3=10
x^2+3-10=0
(x+5)(x-2)=0
x=-5 or x=2

Answer 5

Thank you!