Question

Please help :/ The equation for a circle with center (3,2) and passing through the point (5,6) is:
a. (x-3)^2+(y-2)^2=20
b. (x-2)^2+(y-3)^2=20
c. (x-2)^2+(y-3)^2=12
d. (x-3)^2+(y-2)^2=12

Answer 1

a

Answer 2

well you have the center...your only problem is the radius...do a distance formula from the "passing point" to the center..that's the radius