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Solve & PLS HELP!!! PLEASE 1/4t^3-16t=0
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do you mean like... \[\LARGE \frac{1}{4}t^3-16t=0\]
Yes
factor out a T first
then you have the difference of two squares... can you factor it now?
Not really...
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\[\LARGE t\cdot(\frac14 t^2-16)=0\] now you have t=0 or (1/4)t^2-16=0
Wah???
\[\LARGE \frac {t^2}{4}=16 \longrightarrow t^2=64\] \[\LARGE t=\pm \sqrt{64}\] so you have three solutions... t=0 t=8 t=-8
But isn't it supposed to be two solutions?
not in this case... only when you have quadratic equation... here you have t^3
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O ok then thanks
Never mind, Glad to help )
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