Question

how do i solve this by factoring?

w(w-3)=108

Answer 1

http://www.wolframalpha.com/input/?i=solve+w%28w-3%29%3D108+for+w

Answer 2

w^2-3w-108=0
Now we are looking for the factors of 108 that are 3 from each other.

Answer 3

Let's try 12*9

Answer 4

w^2-3w-108=0
w^2-12w+9w-108=0
W(w-12)+9(w-12)=0(w-12)(w-9)=0
w=12,9

Answer 5

(w+9)(w-12)
or (w-9)(w+12)

Answer 6

since we see -3w, we have (w+9)(w-12).

Answer 7

Not what @Somjit said xD.

Answer 8

k got it, thx sooo much