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I can't figure this out: http://roads.advancedacademics.com/contentserver/content/roadssection/277590/questions/9quiz5/9quiz5_q3.gif A. .0238 B. 1,820 C. 2,380
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\[\frac{16!}{4!12!}\] \[\frac{16\times 15\times 14\times 13\times 12!}{4!12!}\] \[\frac{16\times 15\times 14\times 13}{4\times 3\times 2}\] \[2\times 5\times 14\times 3\]
r u sure?
pretty sure yes
\[\dbinom{16}{4}=\dbinom{16}{12}=1820\]
oh okay thnk u ;)
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