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The half-life of ^60Co (Cobalt-60) is 5.27 years. How long does it take for 50 grams of ^60Co to decay to 20 grams?
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\[^{60}Co\]
\[20=50\times (\frac{1}{2})^{\frac{t}{5.27}}\] solve for t
\[\frac{2}{5}=.4=(\frac{1}{2})^{\frac{t}{5.27}}\] \[\frac{t}{5.27}=\frac{\ln(.4)}{\ln(.5)}\] \[t=\frac{5.27\ln(.4)}{\ln(.5)}\] then a calculator
t = 1.3219, thanks so much! :)
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