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OpenStudy (anonymous):
What is the equation of the hyperbola with vertices at (0,-4) and (0,4) and foci at (0,-6) and (0,6)? a. y^2/16 - x^2/20 =1 b. x^2/16 - y^2/20 =1 c. x^2/16 - y^2/36 =1 d. x^2 - y^2/52 =1
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OpenStudy (mertsj):
a^2=16, c^2=36 a^2+b^2=c^2 If the vertices are (0,4) and (0,-4), what is the center?
OpenStudy (anonymous):
2? I have no idea
OpenStudy (mertsj):
do you know what a hyperbola is?
OpenStudy (anonymous):
yes sort of
OpenStudy (mertsj):
Do you know what the vertex of a hyperbola IS?
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OpenStudy (anonymous):
no
OpenStudy (mertsj):
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