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OpenStudy (anonymous):
sqrt(4y+1)-sqrt(y-2)=3
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Directrix (directrix):
sqrt(4y+1)-sqrt(y-2)=3 sqrt(4y+1) = 3 + sqrt(y-2) [sqrt(4y+1)] ^2 = [ 3 + sqrt(y-2)] ^2 4y + 1 = 9 + 6 sqrt(y-2) + y -2 4y - y + 1 + 2 - 9 = 6 sqrt(y-2) 3y + 3 - 9 = 6 sqrt(y-2) 3y - 6 = 6 sqrt(y-2) y - 2 = 2sqrt(y-2) [y - 2]^2 = [2sqrt(y-2)]^2 (y-2)^2 = 4 ( y - 2) y^2 -4y +4 = 4y - 8 y^2 - 8y + 12 = 0 (y -6) (y-2) = 0 y = 6 or y = 2
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