Question

What is the equation of the parabola in vertex form?

x^2+6x-y+3=0

a. (x+9)=(y-3)^2

b. (x+6)=(y+6)^2

c. (x+3)^2=(y+6)

d. (x+36)=(y+33)^2

Answer 1

y=x^2+6x+3
y=x^2+6x+9-9+3
y=(x+3)^2-6

Answer 2

c. (x+3)^2=(y+6)

Answer 3

i suppose c