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What is the value of p? x^2=12y
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there's no p hahaha :P
so what do I put ? 0
i dont know...im not good with trick questions..wait..ill ask
Indeterminate :D
are you reading the textbook correctly?
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its an online class and yes
ok. this late at night, anyone can miss some words.
no thats what the problem says
and this isn't some funny form of p?
I don't think so ..?
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ok. then ishaan's def got your back. yu good
12 = 4p => p = 12/4 = 3
thank you so much
4py = x²
so the answer is x^2?
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