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Mathematics 15 Online
OpenStudy (anonymous):

f(x) = ln(x^2), x = 4

OpenStudy (anonymous):

is it 2ln(x^)2x Then plug in 4?

OpenStudy (anonymous):

(x^2)*

OpenStudy (anonymous):

I think directly sub. x=4 is fine already

OpenStudy (anonymous):

f(4)=ln(4^2)=ln16

OpenStudy (anonymous):

which can be simplified to 4ln2

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