Question

A boy walks a certain distance at 9km/hr. He find if he increase his speed by 1/3, he would have save 1 1/3 hours. Find the distance he walk?
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Answer 1

d = 9t
d = ( 9 + 1/3*9) ( t - 4/3)

Answer 2

I get t = 16/3

Answer 3

so d = 9*(16/3) = 48 km

Answer 4

Let t be the original time taken
s = x/t, x=st
Therefore
9t = 9 [1+(1/3)] (t- 1 1/3)
9t = 12t -16
t = 16/3

Distance travelled = st = 9 (16/3) = 3 x 16 = 48 km

Sorry i'm slow

Answer 5

thanks dear

Answer 6

* the distance travelled is the same
so s1t1 = s2t2