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A boy walks a certain distance at 9km/hr. He find if he increase his speed by 1/3, he would have save 1 1/3 hours. Find the distance he walk? www.teachon.tk
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d = 9t d = ( 9 + 1/3*9) ( t - 4/3)
I get t = 16/3
so d = 9*(16/3) = 48 km
Let t be the original time taken s = x/t, x=st Therefore 9t = 9 [1+(1/3)] (t- 1 1/3) 9t = 12t -16 t = 16/3 Distance travelled = st = 9 (16/3) = 3 x 16 = 48 km Sorry i'm slow
thanks dear
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* the distance travelled is the same so s1t1 = s2t2
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