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What is the equation of the parabola, in vertex form, with vertex at (2,-4) and directrix y = -6? a. (y+4)^2=8(x-2) b. (y+6)^2=-8(x+2) c. (x+2)^2=8(y+4) d. (x-2)^2=8(y+4)
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must be d
since the vertex is y = -6 the parabola is in the form (y -k)^2 = 4a(x -h) the distance from the directrix to the vertex is 2 so a = 2... the parabola is concave right... (y + 4)^2 = 8(x - 2)
is it A or D ?
its A
its D :/
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