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log2 x = log2 (1-5x)-1 find x
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\[\log_{2} x=\log_{2} (1-5x) - 1 \]
1 can be written as log of 2 to the base 2. use properties to simplify and take anti-log.
@callisto... can help?
\[\log _{2} x - \log _{2} ( 1 - 5x) = -1\] raise each term to a power of 2 \[x - (1 - 5x) = 2^{-1}\] 6x - 1 = 1/2 solve the equation
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