Question

Using complete sentences, explain how to factor each one. Be sure that the final factorization (or "answer") is a part of your explanation.

2x^2 + 13x + 15

Answer 1

Help plzz!

Answer 2

Aren't you supposed to do this assignment yourself and then send it in? :P

Answer 3

@Nightie I dont think so. I just need help solving it.

Answer 4

apoorvk will help you then ;)

Answer 5

ok. ?

Answer 6

He is typing a reply, I assume he is working on giving you a nice solution. Hence my previous response.

Answer 7

@Nightie yeah ot looks like that but i have another problem likethis one i need help on too but i am waiting on this one to be finished.

Answer 8

okay factoring a quadratic is done using what we call "splitting of the middle term".

let the standard quadratic be ax^2 + bx + c.

we basically take all the factors of 'a' and 'c' and rearrange them in two groups, so that subtracting or adding them i get 'b', taking care of the signs ofcourse.

let me show you how.

here we have ----> 2x^2 + 13x + 15

so 'a' and 'c' here are 2 and 15
combined prime factors are 1,2,3,5

so let me group (1,2,3), and (5). i get (1x2x3)+(5) = 6 + 5 =11. this is not equal to 'b' that is 13.

so we try another combination. lets try for (1,2,5) and (3). here, (1x2x5)+(3)= 13

so this one will work!! so we split 13x as 10x+3x

so now i write the expression as:

2x^2+13x+15
= 2x^2 + (10)x + (3)x + 15
= 2x(x+5) + 3(x+5)
= (2x+3)(x+5) <-------

There we are!! hope that cleared things up!!

Answer 9

@apoorvk ur an amzing person! thank you for all ur help.

Answer 10

Good job man!

Answer 11

Don't mention @suzan. that's what we are all here for right?

Answer 12

@apoorvk thats true, can u help me with one more? plz

Answer 13

yeah sure. btw, if its similar, why don't you try yourself for once, and post if you are getting stuck.

Answer 14

Ok, i will try it myself and if i get stuck i will post it.