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Solve. -14 + x² = 5x
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x will hv two values x=7 x=-2
x=-2,7
Consider the equivalent equation : \[x ^{2}-5x-14=0\] introduce \[\Delta=b^2-4ac\] (with a=2, b=5, c =-14). Solutions are \[(-b \pm \sqrt{\Delta})/2a\]
b=-5, sorry.
it can simply be done using middle term splitting..
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