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Ln(x+2)-LN(4x+3)=LN(1/x)
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ln(u) - ln(v) = ln(u/v) so: ln(x+2) - ln(4x+3) = ln((x+2)/(4x+3)) = ln(1/x) => 1/x = (x+2)/(4x+3) now solve like a normal eq.
Then times both sides by 4x+3?
Or by x/1?
both :D do it one at a time though, its easier
you should get 4x+ 3 = x(x+2)
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