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Factor completely 81x2 – 4 a. (2x – 9)(2x + 9) b. (9x – 2)(9x – 2) c. (9x – 2)(9x + 2) d. (2x – 9)(2x – 9)
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Yep, it is C
i assume that is 81*x^2-4 so 81*x^2-4 9^2*x^2-2^2 (9x+2)(9x-2)
The binomial can be factored using the difference of squares formula, because both terms are perfect squares. The difference of squares formula is a^(2)-b^(2)=(a-b)(a+b). (9x-2)(9x+2)
thanks everyone.
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