Question

HELP PIC ADDED !!!

Answer 1

\[(8x)^0(7^7)(7^x)=7^6\]
\[1(7^{7+x})=7^6\]
\[7+x=6\]
\[x=-1\]

Answer 2

Thanks , what about 2 ?

Answer 3

Did you try it yet?

Answer 4

Remember y^5 divided by y^5 = 1

Answer 5

No its confusing idk how :{

Answer 6

6^(-x)y^5 / y^5 = 6^8
= 6^-x * y^5 / y^5 = 6^8
y^5 / y^5 = 1
it leaves you with 6^-x = 6^8

Answer 7

\[\frac{6^{-x}y^5}{y^5}=6^8\]
\[6^{-x}=6^8\]
\[-x=8\]
\[x=-8\]

Answer 8

\[\frac{8^5}{8^x}=8^7\]
\[8^{5-x}=8^7\]
\[5-x=7\]
\[x=-2\]