Question

The perimeter of rectangle is 80 inches...the area is 396 square inches...find length and width

Answer 1

perimeter of rectangle = 2L + 2W = 80
area = LW = 396

you can use substitution to solve...need guide?

Answer 2

i think i can get it

Answer 3

just tell me when you need help :)

Answer 4

i dont understand what you plugin for L & W

Answer 5

2L + 2W = 80
LW = 396
for LW = 396
L=396/W
put this into 2L + 2W = 80
2(396/W) + 2W =80
396/W + W =40
396 +W^2 = 40W
W^2 -40W -396 =0
solve for W, reject -ve value of W
Then sub the value of W into L=396/W to find L

Is the above what you mean, @lgba

Answer 6

thanks coco...thats it!