Question

nerdy girl in need!!!!! what are the solutions to 4(x-1)^2-16=0

Answer 1

2(x-1) + 4 = 0
2(x-1) - 4 = 0

Answer 2

what @GT did was difference of two squares..then equated the factors to 0

Answer 3

4(x-1)^2-16 =0
=>4(x-1)^2 = 16
=> (x-1)^2 = 16/4
=> (x-1)^2 = 4 => 2^2
=> x-1 = 2 OR x-1 = -2
=> x = 2+1 or x = 1-2
=> x=3 or x=-1

Answer 4

4(x-1)^2-16=0

Add 16 to both sides
4(x-1)^2-16 +16=0 +16
4(x-1)^2=16

Divide both sides by 4
4(x-1)^2 /4=16/4
(x-1)^2=4

take square root on both sides
(x-1)= -2 or (x-1)= 2
x = -2+1 = -1 or x = 2+1 = 3

Answer 5

x = 1 ± √ ( 16/4 )
= 3, -1