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OpenStudy (anonymous):
Solve: 4y2 + 12y + 9 = 0
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OpenStudy (anonymous):
hint... \[\LARGE x_{1/2}=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\] substitute.. \[\LARGE a=4 \quad \quad b=12 \quad \quad c=9\]
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