Question

What is the distance between the zoo and the library?
a. 100 feet
b. 300 feet
c. 600 feet
d. 900 feet

Answer 1

distance from helicopter to zoo we'll write with X

since we have angle 60^0 we can use sin x to get X ... so we have..

\[\LARGE \sin \theta =\frac{300\sqrt3}{x}\]

\[\LARGE \sin60^{\circ}=\frac{300\sqrt3}{x}\]

since \[\LARGE \sin60^{\circ}=\frac{\sqrt3}{2}\]

we have...

\[\LARGE \frac{\sqrt3}{2}=\frac{300\sqrt3}{x}\]

now use cross multiply and you should get X...

\[\LARGE x=600\]

now use pythagoras theorem to find distance from G to Zoo

\[\LARGE a^2+b^2=c^2\]

substitute and tell me where are you stucked (if you get stucked somewhere) ...
Good Luck !

Answer 2

or wait... you don't have to do that... we have angle 30^0 we can find distance from point G till to Zoo.... just use Tangent..

do you know how it goes ??

Answer 3

till library ... my mistake ;)

Answer 4

?

Answer 5

distance from G till library write with U

now you have..

\[\LARGE \tan30^{\circ}=\frac{300\sqrt3}{u}\]

find U then use pythagoran theorem and you're done !

Answer 6

@JustCurious Do you understand it ?

Answer 7

not really

Answer 8

what you don't understand ?

Answer 9

Nevermind, thanks for your help!

Answer 10

... No hold on ! ... don't leave without knowing it ! I'll help you more !

Answer 11

\[\Large \tan30^{\circ}=\[\frac{\sqrt3}{3}\]\]
so we have...

\[\LARGE \frac{\sqrt3}{3}=\frac{300\sqrt3}{u}\]

use cross multiply and you'll get

\sqrt(3)*u=3*300*sqrt(3)

can you solve it ..?