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find an equation of the line L that contains points (0,0) and (5,3)
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y=(3/5)x
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The equation of a line is y = mx + b First what you want to do is find the slope. The slope equation is M = y1-y2 over x1-x2 So |dw:1333563749180:dw| the negatives cancel out so it's actually 3/5 Then you want to do is plug the slope into the y = mx + b equation along with a point to find the y - intercept (b) So |dw:1333564228909:dw| Then you just put the equation together |dw:1333564306064:dw| Hope this helps! :D
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