Question

kropot this is the one @kropot72

Answer 1

@kr

Answer 2

\[4^{(x+7)}=6^{(x -1)}\]
\[4^{x}\times4^{7}=6^{x}\div6\]
Grouping like terms on each side:
\[4^{7}\times6=6^{x}\div4^{x}=(6\div4)^{x}\]
Taking logs to base e of each side:
\[\ln (4^{7}\times6)=x \times \ln 1.5\]
\[x=\ln (4^{7}\times6)\div \ln 1.5\]
x=28.35