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Mathematics 18 Online
OpenStudy (anonymous):

solve (3+2i)(2+5i)

jimthompson5910 (jim_thompson5910):

(3+2i)(2+5i) 3*2 + 3*5i + 2i*2 + 2i*5i 6 + 15i + 4i + 10i^2 6 + 15i + 4i + 10(-1) 6 + 15i + 4i - 10 -4 + 19i So (3+2i)(2+5i) = -4 + 19i

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