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Mathematics 23 Online
OpenStudy (anonymous):

Solve for x in terms of a, b, and c. ax^2+bx+c=0

OpenStudy (akshay_budhkar):

Using the quadratic equation the solution for this problem will be \[x={-b \pm \sqrt{b^2 - 4ac}} \over 2a\]

OpenStudy (akshay_budhkar):

\[x= {{-b \pm \sqrt {b^2 - 4ac}} \over 2a }\] is what i mean

OpenStudy (anonymous):

o ok then thanks

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