Please help! Sketch the graph of f(x)=x^2-x by locating the x and y intercepts and the extreme point of the parabola.
The x-intercept(s):
a. = 0 and 1
b. does not exist
c. = 0
d. = 1

Question

Please help! Sketch the graph of f(x)=x^2-x by locating the x and y intercepts and the extreme point of the parabola. 
The x-intercept(s):
a. = 0 and 1
b. does not exist		
c. = 0		
d. = 1

carniel · Answer

We cant graph for you. It would be basically giving you the answer. You wouldn't learn anything from that.

anonymous · Answer

Can you explain to me how I would do this though?

anonymous · Answer

Oh wait, I think I got it... Can you verify? 0 and 1?

carniel · Answer

All you have to do is graph it. Idk how to explain how you graph.... Im a on hands person

anonymous · Answer

here's a hint on graphing parabolas...  they all have basically the same shape and they all either have a maximum or minimum... minimum if the coeficient  of the x^2 term is positive in which case the graph opens upward.  if the coeficient is negative, then parabola opens downward and it has a maximum.

anonymous · Answer

Oh o.k. Thank you for the useful advice!