Question

(8a^4-1/8 b^8)^2

Answer 1

\[\frac{1}{64} \left(8 a^2-b^4\right)^2 \left(8 a^2+b^4\right)^2 \]

Answer 2

\[(8a^4-1\ 8 b^8)^2\]= 1/64