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\[\int\limits x(x-1)^5~dx ---> x=1+u\]\[\int\limits (1+u)(u)^5~du\]How to carry on?
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\[\int\limits u ^{5}dx +\int\limits u ^{6}dx\]
sry, du
\[\int\limits (u ^{5}+u ^{6})du=\int\limits u ^{5}du+ \int\limits u^{6}du\]
u^6 /6 + u^7 / 7 +c
Why u^6?
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u^5 (1+u)= u^6 + u^5
Oh, Ok.
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