Question

help attached

Answer 1

Salam!

Answer 2

Walaikum Salam Saifoo

Answer 3

i will brb in a sec.

Answer 4

@experimentX @eigenschmeigen @sheena101 @order

Answer 5

\[\Large \frac{\frac{x^2 -4}{x-8}}{x-2}\to \frac{\frac{(x-2)(x+2)}{x-8}}{x-2}\]

Answer 6

\[\frac{(x-2)(x+2)}{x-8} \div x-2\]\[\frac{(x-2)(x+2)}{x-8} \times \frac{1}{x-2}\]

Answer 7

you may solve now.. :)

Answer 8

is that first one this:\[\frac{\left(\frac{x^2 - 4}{x-8}\right)}{x-2}\]
or:
\[\frac{x^2-4}{\left(\frac{x-8}{x-2}\right)}\]

Answer 9

neither like has ()

Answer 10

hint for the second one:
\[x^2 - 36 = (x-6)(x+6)\]

Answer 11

i mean, the top division looks slightly smaller so i think @saifoo.khan 's answer is the right one, but it doesn't ever hurt to use brackets to avoid ambiguity