Ask your own question, for FREE!
Physics 15 Online
OpenStudy (anonymous):

A copper wire with a cross-sectional area of 1.2x10^-6(m^2) is connected into a circuit with a constant voltage source. The current in the wire is 1.5mA. The concentration of free electrons in copper is 8.7x10^28(m^-3). Calculate the drift velocity in m/s of electrons in this wire. Where; e = 1.6x10^-19 I = 1.5x10^-3 N = 8.7x10^28 a = 1.2x10^-6 v = ? Using I = nAve, how do you work out v?

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Latest Questions
Arriyanalol: i need help
2 days ago 7 Replies 1 Medal
Arriyanalol: CONGRATS to me
2 days ago 8 Replies 2 Medals
Legomaster346: What colleges are good that are near Arab Alabama?
1 week ago 5 Replies 0 Medals
Arriyanalol: i need help
1 week ago 6 Replies 2 Medals
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!