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A copper wire with a cross-sectional area of 1.2x10^-6(m^2) is connected into a circuit with a constant voltage source. The current in the wire is 1.5mA. The concentration of free electrons in copper is 8.7x10^28(m^-3). Calculate the drift velocity in m/s of electrons in this wire. Where; e = 1.6x10^-19 I = 1.5x10^-3 N = 8.7x10^28 a = 1.2x10^-6 v = ? Using I = nAve, how do you work out v?
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