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The coordinates of quadrilateral FGHJ are F(-5, -3), G(-3,3) , H(3,5) , and J(7,-1). Find the midpoint of FJ.
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Mid point = ( (x1+x2)/2, (y1+y2)/2 ) = ( (-5 +7)/2 , (-3 + -1) /2 ) = can you work it out? Similar to your last question, if you know how to do the last one, you should know this too..
(1,-2)
Got it , thanks !
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