Question

Solve the system of equations.

y = 2x² – 3
y = 3x – 1 (1 point)

no solution
(–1/2, 5), (2, –5/2)
(–1/2, –5/2), (2, 5)
(1/2, 5/2), (2, 5)

Answer 1

subtract and solve \(x^2-3x-2=0\)

Answer 2

Subtract the second from the first. That will give you a quadratic equation in x that gives two values for x. Substitute the values of x to get the values of y.