Question

solve the eqaution, 2sin^2(theta) = sin(theta)+1

Answer 1

bring everything to one side and treat it as a quadratic equation: 2x^2 - x - 1 = 0

Answer 2

bring over then factor,
2sin^2(theta) = sin(theta)+1
2sin^2(theta)- sin(theta)-1= 0
(sinx-1)(2sinx+1)=0
sinx=1 , sinx=-1/2

Answer 3

Thanks Alot