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Write and equation of the line tangent to the given circle at the given point. PLEASE HELP! 1) x^2 + y^2 = 13 (3,-2)
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take the derivative using implicit differentiaton gives \(2x+2yy'=0\) or \[y'=-\frac{x}{y}\] hten replace x by 3 and y by -2 to get your slope. use the point slope formula to find the line
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